Searched defs:i2 (Results 1 - 5 of 5) sorted by relevance
/dalvik/dx/tests/044-dex-math-ops/ |
H A D | Blort.java | 24 public void blort(int i1, int i2) { argument 27 i = i1 + i2; 28 i = i1 - i2; 29 i = i1 * i2; 30 i = i1 / i2; 31 i = i1 % i2; 32 i = i1 & i2; 33 i = i1 | i2; 34 i = i1 ^ i2; 35 i = i1 << i2; [all...] |
/dalvik/libcore/luni/src/main/java/java/lang/ |
H A D | Math.java | 550 * @param i2 552 * @return the larger of {@code i1} and {@code i2}. 554 public static int max(int i1, int i2) { argument 555 return i1 > i2 ? i1 : i2; 652 * @param i2 654 * @return the smaller of {@code i1} and {@code i2}. 656 public static int min(int i1, int i2) { argument 657 return i1 < i2 ? i1 : i2; [all...] |
H A D | StrictMath.java | 542 * @param i2 544 * @return the larger of {@code i1} and {@code i2}. 546 public static int max(int i1, int i2) { argument 547 return i1 > i2 ? i1 : i2; 636 * @param i2 638 * @return the smaller of {@code i1} and {@code i2}. 640 public static int min(int i1, int i2) { argument 641 return i1 < i2 ? i1 : i2; [all...] |
/dalvik/libcore/math/src/test/java/tests/api/java/math/ |
H A D | BigIntegerTest.java | 1167 BigInteger i1 = element[0], i2 = element[1]; 1168 BigInteger res = i1.and(i2); 1169 assertTrue("symmetry of and", res.equals(i2.and(i1))); 1170 int len = Math.max(i1.bitLength(), i2.bitLength()) + 66; 1172 assertTrue("and", (i1.testBit(i) && i2.testBit(i)) == res 1189 BigInteger i1 = element[0], i2 = element[1]; 1190 BigInteger res = i1.or(i2); 1191 assertTrue("symmetry of or", res.equals(i2.or(i1))); 1192 int len = Math.max(i1.bitLength(), i2.bitLength()) + 66; 1194 assertTrue("or", (i1.testBit(i) || i2 1343 testDiv(BigInteger i1, BigInteger i2) argument 1412 testAllMults(BigInteger i1, BigInteger i2, BigInteger ans) argument 1423 testAllDivs(BigInteger i1, BigInteger i2) argument [all...] |
/dalvik/tools/dmtracedump/ |
H A D | TraceDump.c | 3382 uint64_t i2 = ptr->method2->elapsedInclusive; local 3384 ptr->differenceInclusive = i2 - i1; 3385 ptr->differenceInclusivePercentage = ((double)i2 / (double)i1) * 100.0;
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