Searched defs:mday (Results 1 - 1 of 1) sorted by relevance

/external/icu4c/i18n/
H A Dindiancal.cpp293 int32_t leapMonth, IndianYear, yday, IndianMonth, IndianDayOfMonth, mday; local
316 mday = yday - leapMonth;
317 if (mday < (31 * 5)) {
318 IndianMonth = (int32_t)uprv_floor(mday / 31) + 1;
319 IndianDayOfMonth = (mday % 31) + 1;
321 mday -= 31 * 5;
322 IndianMonth = (int32_t)uprv_floor(mday / 30) + 6;
323 IndianDayOfMonth = (mday % 30) + 1;

Completed in 46 milliseconds