linked_list.h revision c7f5f8508d98d5952d42ed7648c2a8f30a4da156
1// Copyright (c) 2009 The Chromium Authors. All rights reserved. 2// Use of this source code is governed by a BSD-style license that can be 3// found in the LICENSE file. 4 5#ifndef BASE_LINKED_LIST_H_ 6#define BASE_LINKED_LIST_H_ 7 8// Simple LinkedList type. (See the Q&A section to understand how this 9// differs from std::list). 10// 11// To use, start by declaring the class which will be contained in the linked 12// list, as extending LinkNode (this gives it next/previous pointers). 13// 14// class MyNodeType : public LinkNode<MyNodeType> { 15// ... 16// }; 17// 18// Next, to keep track of the list's head/tail, use a LinkedList instance: 19// 20// LinkedList<MyNodeType> list; 21// 22// To add elements to the list, use any of LinkedList::Append, 23// LinkNode::InsertBefore, or LinkNode::InsertAfter: 24// 25// LinkNode<MyNodeType>* n1 = ...; 26// LinkNode<MyNodeType>* n2 = ...; 27// LinkNode<MyNodeType>* n3 = ...; 28// 29// list.Append(n1); 30// list.Append(n3); 31// n3->InsertBefore(n3); 32// 33// Lastly, to iterate through the linked list forwards: 34// 35// for (LinkNode<MyNodeType>* node = list.head(); 36// node != list.end(); 37// node = node->next()) { 38// MyNodeType* value = node->value(); 39// ... 40// } 41// 42// Or to iterate the linked list backwards: 43// 44// for (LinkNode<MyNodeType>* node = list.tail(); 45// node != list.end(); 46// node = node->previous()) { 47// MyNodeType* value = node->value(); 48// ... 49// } 50// 51// Questions and Answers: 52// 53// Q. Should I use std::list or base::LinkedList? 54// 55// A. The main reason to use base::LinkedList over std::list is 56// performance. If you don't care about the performance differences 57// then use an STL container, as it makes for better code readability. 58// 59// Comparing the performance of base::LinkedList<T> to std::list<T*>: 60// 61// * Erasing an element of type T* from base::LinkedList<T> is 62// an O(1) operation. Whereas for std::list<T*> it is O(n). 63// That is because with std::list<T*> you must obtain an 64// iterator to the T* element before you can call erase(iterator). 65// 66// * Insertion operations with base::LinkedList<T> never require 67// heap allocations. 68// 69// Q. How does base::LinkedList implementation differ from std::list? 70// 71// A. Doubly-linked lists are made up of nodes that contain "next" and 72// "previous" pointers that reference other nodes in the list. 73// 74// With base::LinkedList<T>, the type being inserted already reserves 75// space for the "next" and "previous" pointers (base::LinkNode<T>*). 76// Whereas with std::list<T> the type can be anything, so the implementation 77// needs to glue on the "next" and "previous" pointers using 78// some internal node type. 79 80namespace base { 81 82template <typename T> 83class LinkNode { 84 public: 85 LinkNode() : previous_(0), next_(0) {} 86 LinkNode(LinkNode<T>* previous, LinkNode<T>* next) 87 : previous_(previous), next_(next) {} 88 89 // Insert |this| into the linked list, before |e|. 90 void InsertBefore(LinkNode<T>* e) { 91 this->next_ = e; 92 this->previous_ = e->previous_; 93 e->previous_->next_ = this; 94 e->previous_ = this; 95 } 96 97 // Insert |this| into the linked list, after |e|. 98 void InsertAfter(LinkNode<T>* e) { 99 this->next_ = e->next_; 100 this->previous_ = e; 101 e->next_->previous_ = this; 102 e->next_ = this; 103 } 104 105 // Remove |this| from the linked list. 106 void RemoveFromList() { 107 this->previous_->next_ = this->next_; 108 this->next_->previous_ = this->previous_; 109 } 110 111 LinkNode<T>* previous() const { 112 return previous_; 113 } 114 115 LinkNode<T>* next() const { 116 return next_; 117 } 118 119 // Cast from the node-type to the value type. 120 const T* value() const { 121 return static_cast<const T*>(this); 122 } 123 124 T* value() { 125 return static_cast<T*>(this); 126 } 127 128 private: 129 LinkNode<T>* previous_; 130 LinkNode<T>* next_; 131}; 132 133template <typename T> 134class LinkedList { 135 public: 136 // The "root" node is self-referential, and forms the basis of a circular 137 // list (root_.next() will point back to the start of the list, 138 // and root_->previous() wraps around to the end of the list). 139 LinkedList() : root_(&root_, &root_) {} 140 141 // Appends |e| to the end of the linked list. 142 void Append(LinkNode<T>* e) { 143 e->InsertBefore(&root_); 144 } 145 146 LinkNode<T>* head() const { 147 return root_.next(); 148 } 149 150 LinkNode<T>* tail() const { 151 return root_.previous(); 152 } 153 154 const LinkNode<T>* end() const { 155 return &root_; 156 } 157 158 private: 159 LinkNode<T> root_; 160}; 161 162} // namespace base 163 164#endif // BASE_LINKED_LIST_H_ 165