/* * [The "BSD license"] * Copyright (c) 2010 Terence Parr * All rights reserved. * * Redistribution and use in source and binary forms, with or without * modification, are permitted provided that the following conditions * are met: * 1. Redistributions of source code must retain the above copyright * notice, this list of conditions and the following disclaimer. * 2. Redistributions in binary form must reproduce the above copyright * notice, this list of conditions and the following disclaimer in the * documentation and/or other materials provided with the distribution. * 3. The name of the author may not be used to endorse or promote products * derived from this software without specific prior written permission. * * THIS SOFTWARE IS PROVIDED BY THE AUTHOR ``AS IS'' AND ANY EXPRESS OR * IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE IMPLIED WARRANTIES * OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE ARE DISCLAIMED. * IN NO EVENT SHALL THE AUTHOR BE LIABLE FOR ANY DIRECT, INDIRECT, * INCIDENTAL, SPECIAL, EXEMPLARY, OR CONSEQUENTIAL DAMAGES (INCLUDING, BUT * NOT LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS OR SERVICES; LOSS OF USE, * DATA, OR PROFITS; OR BUSINESS INTERRUPTION) HOWEVER CAUSED AND ON ANY * THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT LIABILITY, OR TORT * (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY OUT OF THE USE OF * THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF SUCH DAMAGE. */ package org.antlr.codegen; public class JavaScriptTarget extends Target { /** Convert an int to a JavaScript Unicode character literal. * * The current JavaScript spec (ECMA-262) doesn't provide for octal * notation in String literals, although some implementations support it. * This method overrides the parent class so that characters will always * be encoded as Unicode literals (e.g. \u0011). */ public String encodeIntAsCharEscape(int v) { String hex = Integer.toHexString(v|0x10000).substring(1,5); return "\\u"+hex; } /** Convert long to two 32-bit numbers separted by a comma. * JavaScript does not support 64-bit numbers, so we need to break * the number into two 32-bit literals to give to the Bit. A number like * 0xHHHHHHHHLLLLLLLL is broken into the following string: * "0xLLLLLLLL, 0xHHHHHHHH" * Note that the low order bits are first, followed by the high order bits. * This is to match how the BitSet constructor works, where the bits are * passed in in 32-bit chunks with low-order bits coming first. * * Note: stole the following two methods from the ActionScript target. */ public String getTarget64BitStringFromValue(long word) { StringBuffer buf = new StringBuffer(22); // enough for the two "0x", "," and " " buf.append("0x"); writeHexWithPadding(buf, Integer.toHexString((int)(word & 0x00000000ffffffffL))); buf.append(", 0x"); writeHexWithPadding(buf, Integer.toHexString((int)(word >> 32))); return buf.toString(); } private void writeHexWithPadding(StringBuffer buf, String digits) { digits = digits.toUpperCase(); int padding = 8 - digits.length(); // pad left with zeros for (int i=1; i<=padding; i++) { buf.append('0'); } buf.append(digits); } }