xref: /device/linaro/bootloader/edk2/EdkCompatibilityPkg/Foundation/Library/EfiCommonLib/Ia32/EfiCopyMemSSE2.c

/*++

Copyright (c) 2006 - 2010, Intel Corporation. All rights reserved.<BR>
This program and the accompanying materials
are licensed and made available under the terms and conditions of the BSD License
which accompanies this distribution.  The full text of the license may be found at
http://opensource.org/licenses/bsd-license.php

THE PROGRAM IS DISTRIBUTED UNDER THE BSD LICENSE ON AN "AS IS" BASIS,
WITHOUT WARRANTIES OR REPRESENTATIONS OF ANY KIND, EITHER EXPRESS OR IMPLIED.

Module Name:

  EfiCopyMemSSE2.c

Abstract:

  This is the code that supports IA32-optimized CopyMem service

--*/

#include "Tiano.h"

VOID
EfiCommonLibCopyMem (
  IN VOID   *Destination,
  IN VOID   *Source,
  IN UINTN  Count
  )
/*++

Routine Description:

  Copy Length bytes from Source to Destination.

Arguments:

  Destination - Target of copy

  Source      - Place to copy from

  Length      - Number of bytes to copy

Returns:

  None

--*/
{
  __asm {
  mov   ecx, Count
  mov   esi, Source
  mov   edi, Destination

  ; First off, make sure we have no overlap. That is to say,
  ;   if (Source == Destination)           => do nothing
  ;   if (Source + Count <= Destination)   => regular copy
  ;   if (Destination + Count <= Source)   => regular copy
  ;   otherwise, do a reverse copy
  mov   eax, esi
  add   eax, ecx                      ; Source + Count
  cmp   eax, edi
  jle   _StartByteCopy

  mov   eax, edi
  add   eax, ecx                      ; Dest + Count
  cmp   eax, esi
  jle   _StartByteCopy

  cmp   esi, edi
  je    _CopyMemDone
  jl    _CopyOverlapped               ; too bad -- overlaps

  ; Pick up misaligned start bytes to get destination pointer 4-byte aligned
_StartByteCopy:
  cmp   ecx, 0
  je    _CopyMemDone                ; Count == 0, all done
  mov   edx, edi
  and   dl, 3                       ; check lower 2 bits of address
  test  dl, dl
  je    SHORT _CopyBlocks           ; already aligned?

  ; Copy a byte
  mov   al, BYTE PTR [esi]          ; get byte from Source
  mov   BYTE PTR [edi], al          ; write byte to Destination
  dec    ecx
  inc   edi
  inc   esi
  jmp   _StartByteCopy               ; back to top of loop

_CopyBlocks:
  ; Compute how many 64-byte blocks we can clear
  mov   eax, ecx                    ; get Count in eax
  shr   eax, 6                      ; convert to 64-byte count
  shl   eax, 6                      ; convert back to bytes
  sub   ecx, eax                    ; subtract from the original count
  shr   eax, 6                      ; and this is how many 64-byte blocks

  ; If no 64-byte blocks, then skip
  cmp   eax, 0
  je    _CopyRemainingDWords


copyxmm:

  movdqu xmm0, OWORD PTR ds:[esi]
  movdqu OWORD PTR ds:[edi], xmm0
  movdqu xmm1, OWORD PTR ds:[esi+16]
  movdqu OWORD PTR ds:[edi+16], xmm1
  movdqu xmm2, OWORD PTR ds:[esi+32]
  movdqu OWORD PTR ds:[edi+32], xmm2
  movdqu xmm3, OWORD PTR ds:[esi+48]
  movdqu OWORD PTR ds:[edi+48], xmm3

  add   edi, 64
  add   esi, 64
  dec   eax
  jnz   copyxmm


  ; Copy as many DWORDS as possible
_CopyRemainingDWords:
  cmp   ecx, 4
  jb    _CopyRemainingBytes

  mov   eax, DWORD PTR [esi]        ; get data from Source
  mov   DWORD PTR [edi], eax        ; write byte to Destination
  sub   ecx, 4                      ; decrement Count
  add   esi, 4                      ; advance Source pointer
  add   edi, 4                      ; advance Destination pointer
  jmp   _CopyRemainingDWords        ; back to top

_CopyRemainingBytes:
  cmp   ecx, 0
  je    _CopyMemDone
  mov   al, BYTE PTR [esi]          ; get byte from Source
  mov   BYTE PTR [edi], al          ; write byte to Destination
  dec    ecx
  inc    esi
  inc   edi                      ; advance Destination pointer
  jmp   SHORT _CopyRemainingBytes   ; back to top of loop

  ;
  ; We do this block if the source and destination buffers overlap. To
  ; handle it, copy starting at the end of the source buffer and work
  ; your way back. Since this is the atypical case, this code has not
  ; been optimized, and thus simply copies bytes.
  ;
_CopyOverlapped:

  ; Move the source and destination pointers to the end of the range
  add   esi, ecx                      ; Source + Count
  dec    esi
  add   edi, ecx                      ; Dest + Count
  dec    edi

_CopyOverlappedLoop:
  cmp   ecx, 0
  je    _CopyMemDone
  mov   al, BYTE PTR [esi]          ; get byte from Source
  mov   BYTE PTR [edi], al          ; write byte to Destination
  dec    ecx
  dec    esi
  dec   edi
  jmp   _CopyOverlappedLoop         ; back to top of loop

_CopyMemDone:
  }
}