1/*
2 * Copyright (C) 2013 The Android Open Source Project
3 * All rights reserved.
4 *
5 * Redistribution and use in source and binary forms, with or without
6 * modification, are permitted provided that the following conditions
7 * are met:
8 *  * Redistributions of source code must retain the above copyright
9 *    notice, this list of conditions and the following disclaimer.
10 *  * Redistributions in binary form must reproduce the above copyright
11 *    notice, this list of conditions and the following disclaimer in
12 *    the documentation and/or other materials provided with the
13 *    distribution.
14 *
15 * THIS SOFTWARE IS PROVIDED BY THE COPYRIGHT HOLDERS AND CONTRIBUTORS
16 * "AS IS" AND ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT
17 * LIMITED TO, THE IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS
18 * FOR A PARTICULAR PURPOSE ARE DISCLAIMED. IN NO EVENT SHALL THE
19 * COPYRIGHT OWNER OR CONTRIBUTORS BE LIABLE FOR ANY DIRECT, INDIRECT,
20 * INCIDENTAL, SPECIAL, EXEMPLARY, OR CONSEQUENTIAL DAMAGES (INCLUDING,
21 * BUT NOT LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS OR SERVICES; LOSS
22 * OF USE, DATA, OR PROFITS; OR BUSINESS INTERRUPTION) HOWEVER CAUSED
23 * AND ON ANY THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT LIABILITY,
24 * OR TORT (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY OUT
25 * OF THE USE OF THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF
26 * SUCH DAMAGE.
27 */
28
29// Contains an implementation of all stdlib functions missing from bionic.
30//
31// TODO(digit): Make these work.
32
33#include <inttypes.h>
34#include <stdlib.h>
35#include <assert.h>
36
37long double strtold(const char* nptr, char** endptr) {
38  //FIXME: Although in Android long double is the same as double, can we borrow stdtod?
39  return strtod(nptr, endptr);
40}
41
42intmax_t imaxabs(intmax_t j)
43{
44  return (j < 0 ? -j : j);
45}
46
47imaxdiv_t imaxdiv(intmax_t numer, intmax_t denom)
48{
49  imaxdiv_t retval;
50
51  retval.quot = numer / denom;
52  retval.rem = numer % denom;
53  if (numer >= 0 && retval.rem < 0) {
54    retval.quot++;
55    retval.rem -= denom;
56  }
57  return (retval);
58}
59