1# Copyright (c) 2009 Google Inc. All rights reserved.
2# Copyright (c) 2009 Apple Inc. All rights reserved.
3#
4# Redistribution and use in source and binary forms, with or without
5# modification, are permitted provided that the following conditions are
6# met:
7#
8#     * Redistributions of source code must retain the above copyright
9# notice, this list of conditions and the following disclaimer.
10#     * Redistributions in binary form must reproduce the above
11# copyright notice, this list of conditions and the following disclaimer
12# in the documentation and/or other materials provided with the
13# distribution.
14#     * Neither the name of Google Inc. nor the names of its
15# contributors may be used to endorse or promote products derived from
16# this software without specific prior written permission.
17#
18# THIS SOFTWARE IS PROVIDED BY THE COPYRIGHT HOLDERS AND CONTRIBUTORS
19# "AS IS" AND ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT
20# LIMITED TO, THE IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR
21# A PARTICULAR PURPOSE ARE DISCLAIMED. IN NO EVENT SHALL THE COPYRIGHT
22# OWNER OR CONTRIBUTORS BE LIABLE FOR ANY DIRECT, INDIRECT, INCIDENTAL,
23# SPECIAL, EXEMPLARY, OR CONSEQUENTIAL DAMAGES (INCLUDING, BUT NOT
24# LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS OR SERVICES; LOSS OF USE,
25# DATA, OR PROFITS; OR BUSINESS INTERRUPTION) HOWEVER CAUSED AND ON ANY
26# THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT LIABILITY, OR TORT
27# (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY OUT OF THE USE
28# OF THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF SUCH DAMAGE.
29
30import re
31
32
33def plural(noun):
34    # This is a dumb plural() implementation that is just enough for our uses.
35    if re.search("h$", noun):
36        return noun + "es"
37    else:
38        return noun + "s"
39
40
41def pluralize(noun, count):
42    if count != 1:
43        noun = plural(noun)
44    return "%d %s" % (count, noun)
45
46
47def join_with_separators(list_of_strings, separator=', ', only_two_separator=" and ", last_separator=', and '):
48    if not list_of_strings:
49        return ""
50    if len(list_of_strings) == 1:
51        return list_of_strings[0]
52    if len(list_of_strings) == 2:
53        return only_two_separator.join(list_of_strings)
54    return "%s%s%s" % (separator.join(list_of_strings[:-1]), last_separator, list_of_strings[-1])
55